berapakah nilai ydari persamaan 4y-8=2y+6
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Diketahui :
4y - 8 = 2y + 6
Ditanya :
Berapakah nilai y dari persamaan 4y - 8 = 2y + 6
Dijawab :
4y - 8 = 2y + 6
=> 4y - 2y = 6 + 8
=> 6y = 14
=> 7
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→ 4y - 8 = 2y + 6
→ 4y - 2y = 6 + 8
→ 2y = 14
→ y = 7
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
[answer.2.content]
